NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: A simple three-body fix puzzle
From: UNK
Date: 2010 Dec 10, 21:08 +0000
From: UNK
Date: 2010 Dec 10, 21:08 +0000
Greg, The correct solution for the MPP is in your second diagram, exactly where you circled it. All you needed to do was to drop the altitude from P onto the hypotenuse and bisect it. This is the so-called symmedian point or Lemoine point. The Gergonne point has nothing to do with our problem. It is NOT the symmedian point. On 2010-12-10 20:32, Greg Rudzinski wrote: > > Herbert, > > Could you inspect and comment on the linked diagrams. > > The first linked diagram shows a 30°/60°/90° triangle plot with > bisected vertex, internal circle tangents, vertex to tangent > intersections (symmedian or Gergonne point), and the d/2 circle around > point P. > (very busy plot) > > The Gergonne point (Gp) seems to be dependent on the bisected angle > point (Bp). Point Bp weighs each LOP equally and point Gp shifts away > from the smallest angle and toward the largest angle. The d/2 circle > intersects at three points along the bisection and tangent lines. > > The question now is which point is correct ? Gp or one of the three > d/2 intersections ? If I had to guess then I would select the > intersection of the d/2 circle, P perpendicular, and 60° vertex to > inner circle tangent (see second linked diagram) > > Greg Rudzinski > ---------------------------------------------------------------- > NavList message boards and member settings: www.fer3.com/NavList > Members may optionally receive posts by email. > To cancel email delivery, send a message to NoMail[at]fer3.com > ---------------------------------------------------------------- > >File:>File:>
