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    Re: recommendation for slide rule ?
    From: Gary LaPook
    Date: 2009 May 21, 15:20 -0700

    And using the Bygrave you get Hc  71�17' and Az of 45�09' the same
    result, see http://www.fer3.com/arc/m2.aspx?i=107414&y=200902.
    
    gl
    
    On May 21, 7:40�am, Brad Morris  wrote:
    > Hi Gary
    >
    > The values, using electronics are
    >
    > Hc = 71.29011 �(71 deg 17 minutes)
    >
    > Az = 44.57333 �(44 deg 34 minutes) when using 71.1
    > Or
    > Az = 45.12870 �(45 deg 08 minutes) when using 72.29011
    >
    > The deltas, compared to the K&E 4080, are
    >
    > delta Hc = (71.29011 - 71.1) = 0.19011 �(0 deg 11.4 minutes)
    > delta Az = (45.12870 - 44.5) = 0.62870 �(0 deg 37.7 minutes)
    >
    > Plotting with an azimuth with an error of less than 1 degree is unlikely to 
    cause problems, except with very shallow LOP crossings.
    > The delta Hc is a larger concern, making this method probably suitable only to deep water sailings.
    >
    > Workable? Yes!
    >
    > Best Regards
    > Brad
    >
    > -----Original Message-----
    > From: NavList@fer3.com [mailto:NavList@fer3.com] On Behalf Of glap...{at}PACBELL.NET
    > Sent: Wednesday, May 20, 2009 7:00 PM
    > To: NavList@fer3.com
    > Subject: [NavList 8339] Re: recommendation for slide rule ?
    >
    > Computing Hc and Zn on a slide rule takes 16 steps. It will be easier to 
    explain with an example, using 34 for the latitude, 20 for the declination 
    and 14 for LHA, the same values used in my previous example with the Flat 
    Bygrave, seehttp://www.fer3.com/arc/m2.aspx?i=107414&y=200902
    >
    > I will use a K&E 4080 for the illustrations.
    >
    > Using the sine- cosine procedure we first calculate Hc using the formula, 
    sin Hc = (sin Lat sin Dec) + (cos Lat cos Dec cos LHA).
    >
    > First line up the sine (S) scale with the D scale, see IMAGP5888.
    >
    > Second move the cursor to the latitude, 34, on the S scale, see -98.
    >
    > Since the sine and cosine values are all less than 1 we know that when we 
    multiply these values that the product will be smaller than the original 
    numbers which on a slide rule means that the result is found further to the 
    left on the scale. So, third, line up the 90 mark on the S scale with the 
    cursor, see -00.
    >
    > Fourth, move the cursor to the declination, 20, on the S scale and read out 
    on the D scale the product of sine latitude and sine declination, .1915. see 
    - 02.
    >
    > Fifth, line up the S and D scale again, see -88.
    >
    > Sixth, move the cursor to the latitude, 34, on the cosine scale, red numbers 
    on the S scale increasing right to left, see -04.
    >
    > Seventh, line up the 90 mark on the S scale with the cursor, see -05.
    >
    > Eighth, move the cursor to declination, 20, on the cosine scale, see -07.
    >
    > Ninth, line up the 90 mark on the S scale with the cursor, see -09.
    >
    > Tenth, move the cursor to LHA, 14, on the cosine scale and read out the 
    product of cosine latitude, cosine declination and cosine LHA on the D scale, 
    .755, see -11.
    >
    > Eleventh, add the two products together, .1915 plus .755 equals .9465.
    >
    > Twelve, line up the S and D scale again and locate .9465 on the D scale and 
    read out Hc on the S scale, 71.1� , see -13.
    >
    > Next we calculate Az using the formula (sin LHA cos Dec)/ cos Hc rearranged 
    as (sin LHA/cos Hc) cos Dec. Az will be in the range of 0 to 90.
    >
    > Thirteen, move the cursor to LHA, 14, on the S scale, see -15.
    >
    > Fourteen, line up Hc, 71.1, on the cosine scale with the cursor, see -26.
    >
    > Fifteen, move the cursor to declination, 14, on the cosine scale, see -27.
    >
    > And finally, sixteen line up the S and D scales and read out Az, 44.5�, on 
    the S scale under the cursor, see -28.
    >
    > gl
    >
    > ,
    >
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