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Re: A noon sight conundrum
From: Paul Hirose
Date: 2003 Dec 1, 15:02 -0800
From: Paul Hirose
Date: 2003 Dec 1, 15:02 -0800
Kieran Kelly wrote: > > 3) In your learned opinion what was the time of meridian passage on that day > at long 132d 40' E. I'll use MICA 1.52 again, but this time working the problem with local hour angle rather than azimuth as I did earlier. MICA doesn't seem to have a way to display local hour angles, so I have to get tabulations of sidereal time and the Sun's right ascension, then subtract one from the other. SIDEREAL TIME Location: E132?40'00", S21?48'18", 0m (Longitude referred to Greenwich meridian) Local App. Date Time Sidereal Time (UT1) h m s h m s 2002 Jul 20 03:15:38.0 7 57 14.4944 2002 Jul 20 03:15:39.0 7 57 15.4972 2002 Jul 20 03:15:40.0 7 57 16.4999 Sun Apparent Topocentric Positions True Equator and Equinox of Date Location: E132?40'00", S21?48'18", 0m (Longitude referred to Greenwich meridian) Date Time Right Ascension (UT1) h m s h m s 2002 Jul 20 03:15:38.0 7 57 15.607 2002 Jul 20 03:15:39.0 7 57 15.610 2002 Jul 20 03:15:40.0 7 57 15.613 The differences: UT1 LAST-RA 03:15:38 23:59:58.9 03:15:39 23:59:59.9 03:15:40 00:00:00.9 Meridian passage occurs .1 s after the middle time, i.e., at 03:15:39.1 UT1. On that date UT1 was .23 s behind UTC, so the UTC time was 03:15:39.3. As I said before, on this date MICA overestimates the TT-UT1 difference by 3.6 seconds. So the Sun's UT1 position against the fixed stars is computed for a time 3.6 seconds later than the correct time. In 3.6 s its right ascension increases .01 s, so strictly speaking all the RA's I tabulated above should be decreased by .01 s to put them on the UT1 time scale. That's too small to worry about.