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Re: napier and logarithms
From: Dave Walden
Date: 2009 May 28, 10:40 -0700
From: Dave Walden
Date: 2009 May 28, 10:40 -0700
A number with 3011 places must be between 1*10**3010 and 10*10**3010. Or equivalently, between 10**3010 and 10**3011. Since this is 2**10,000, let's take the 10,000th root of both sides. If lower end of range: 2**10,000 = 10**3010 take the root by dividing the exponents by 10,000: 2**(10,000/10,000)=10**(3010/10,000) 2**1=10**.3010 2=10**.3010 log 2 =.3010 If upper end of range, same method; log 2 =.3011 So it's somewhere in between. Why not guess .30105? In fact, 10**.30105=2.000092126 or so. --~--~---------~--~----~------------~-------~--~----~ Navigation List archive: www.fer3.com/arc To post, email NavList@fer3.com To , email NavList-@fer3.com -~----------~----~----~----~------~----~------~--~---
