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    Re: e for Clarke 1866 was Re: Silicon Sea : Leg 69
    From: Dan Hogan
    Date: 2001 Apr 11, 09:40 EDT

    On 10 Apr 2001, at 22:48, Sam Chan wrote:
    >
    > What is e for the Clarke. I have spreadsheets set up to generate tables of
    > Meridional Parts and Latitude Parts. I would like to see what this will do
    > to the calculation.
    Sam:
    Clarke of 1886 e= .08199188997
    Personal Opinion -- Changeing ellipsoids for *parctical* navigation does
                        not provide enough diffrerance in to make the extra
                                            worth while.
    However it makes interesting experiments for us chair bound navigators.
    Cheers
    -Dan-
    

       
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