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    Re: A celestial navigation problem
    From: Mike Burkes
    Date: 2011 Nov 28, 18:55 -0800

    Hi folks,after deciphering all the solutions,unless I am missing something really dumb and discussing watch error how is the latter figured into the solution? Here is my solution and I interpolated for LAN using equal altitudes.
    Sight AM Hs PM AM+PM LAN=Total/2
    2 18-02-45 77 44.1 18-13-27 36-15-32 18-07-46
    3 18-04-05 77 46.8 18-11-19 36-15-24 18-07-42
    4 18-06-05 77 48.3 18-09-14 36-15-19 18-07-40
    5 18-07-25 77 48.7 18-07-50 36-14-75 18-07-38
    9 18-09-05 77 48.4 18-06-25 36-15-30 18-07-45
    Total 90-35-211
    Average 18-07-42= LAN
    WE -5 fast
    ZT 18-07-37
    ZD +4
    UT LAN 22-07-37
    GHA 22 hr 149 53.6
    increments 7m 37s 1 54.3
    Longitude 151 47.9 W
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