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    Re: Wind & Current Navigation
    From: Dave Weilacher
    Date: 2003 Apr 17, 08:21 -0400

    ...so would a 2 knot current be the sqrt((2^2) * 830) = 58kt wind?
    
    
    -------Original Message-------
    From: George Huxtable 
    Sent: 04/17/03 10:16 AM
    To: NAVIGATION-L@LISTSERV.WEBKAHUNA.COM
    Subject: Re: Wind & Current Navigation
    
    
    At the same rate of flow, the water force would be about 830 times
    greater,
    because water is denser than air by that factor. The force will vary as
    the
    square of the velocity, so the force due to a 1 knot tide on the buoy
    would
    be equivalent to the force of a breeze of nearly 30 knots (28 being the
    square root of 830, roughly). That gives an idea of the order-of-magnitude
    of differences between water forces and wind forces.
    
    
    
    Dave Weilacher
    .US Coast Guard licensed captain
    .    #889968
    .ASA instructor evaluator and celestial
    .    navigation instructor #990800
    .IBM AS400 RPG contract programmer
    
    
    

       
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