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    Re: In the Wake of Magellan
    From: Robert H. van Gent
    Date: 2019 Oct 11, 07:58 +0000

    Hi,

     

    Regarding your first question you may find these recent papers by Siebren van der Werf useful

     

      https://journals.sagepub.com/doi/full/10.1177/0021828617705244

     

      https://journals.sagepub.com/doi/full/10.1177/0021828619864472

     

    Regarding your second question you could also add the mariner’s astrolabe as a possible observing instrument.

     

    Rob van Gent

     

    From: NavList@fer3.com <NavList@fer3.com> On Behalf Of Doug MacPherson
    Sent: Thu 10 October 2019 20:32
    To: Gent, R.H. van (Rob) <R.H.vanGent{at}uu.nl>
    Subject: [NavList] In the Wake of Magellan

     

    Recently sailing in my armchair I was pondering the navigational challenges Magellan and other European sailors of his time must have experienced. (Early 16th century).  

    I assume that the sun was the primary source of information for determinig latitude and that they had some table showing them the declination of the sun over the course of the year.

    Three questions came to mind:

    1. Where did the sun's declination table come from?  Did the Spanish, Portuguese or other governments supply it? How did they get it?

    2. What tool were they using to determine the altitude of the sun at noon?  A cross staff? kamal? backstaff?  John Davis Did not invent his "Davis" quadrant (a backstaff) till 1594.

    3. If, in an unfortunate accident, the declination table blew overboard, and our intrepid captain remembered that the sun's declination was about 23.45° South and North on December 21 and June 21 respectively, and 0° on March 21 and September 21, would a linear approximation of the sun's declination from that rememebered data be accurate enough to navigate with?  What would be the max error from the sun's actual declination and when would that occur?

    Finally, would the max error matter given the tools they were using?

    Cheers,

    Doug 

    38° 34.3' N

    121° 28.5' W

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