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Darn it George, it isn't easy being the dumbest person in the room.
Therefore. how could I guess what it might feel like to be the smartest
person on the room;-)

We start with a approx 6.4d difference in declination, back out the sun's
SD, and account for refraction, would the separation not be greater than 3d?
The list would indicate bodies near the horizon may be extinguished near the
horizon, but I have no clue as to the angular distance for a body the
almanac lists as -3.7 magnitude for that 3-day period.

Given my mental prowess, "hope" is all I have to go on. 

Bill

Bill wrote-
>
>> About sunset at N 40d 28' W 86d 56' January 13,
>> 2006 the suns declination will be approx. S22d 22' and Venus's S15d 56'.
>> So
>> for several minutes after sunset Venus will be above the horizon.  With a
>> difference of 6d 26' declination, a sliver of Venus's lower limb should be
>> illuminated .  As Venus will be approx. 1 arc minute in diameter, a 30
>> power
>> telescope should make it quite visible for a couple of minutes.
>
> I doubt if Bill will have much hope of seeing Venus under those
> circumstances. The difference in altitude between Venus and Sun will only be
> 3 degrees or so. And it would be asking for trouble to start looking before
> the Sun has completely set.
>
> George

   

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