NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: USCG Student Sample Problem #4
From: Peter Hakel
Date: 2013 Apr 27, 15:08 -0700
From: Peter Hakel
Date: 2013 Apr 27, 15:08 -0700
Hi Kermit,
My results are the same as yours:
SD = 16.117' (after removing the rounding); agrees with 16.1' from NA: 2013 Commercial Edition
Intercept: 19.8' Away
Azimuth: 126.2
Cheers,
Peter Hakel
From: Antoine Couëtte <antoine.m.couette@club-internet.fr>
To: pmh099@yahoo.com
Sent: Saturday, April 27, 2013 1:16 PM
Subject: [NavList] Re: USCG Student Sample Problem #4
You wrote :
My results are the same as yours:
SD = 16.117' (after removing the rounding); agrees with 16.1' from NA: 2013 Commercial Edition
Intercept: 19.8' Away
Azimuth: 126.2
Cheers,
Peter Hakel
From: Antoine Couëtte <antoine.m.couette@club-internet.fr>
To: pmh099@yahoo.com
Sent: Saturday, April 27, 2013 1:16 PM
Subject: [NavList] Re: USCG Student Sample Problem #4
RE : http://fer3.com/arc/m2.aspx/USCG-Student-Sample-Problem-4-Rudzinski-apr-2013-g23703
Hello Greg,
You wrote :
QUOTE
My guess on the Sun difference of 0.2' would be the way rounding of semi diameter is done between your program and USNO.
UNQUOTE
I would surprised that USNO would make such a 0.2' rounding on the SUN Semi-Diameter which is very well known and changes very slowly. On my side, I do not round the SUN SD and do not use any Irradiation factor either. For this example I am using SD = 16'117 (same value as the 16'1 you have published).
How about getting third party results ?
Peter, Andrés or Yves (or others) ?
From : Nov 01 st, 2013 at UT 22:59:53 / N 26° / E 143°55'3 , with HOE = + 100
ft , standard conditions and Sextant Height (already corrected for Instrument Error) equal to 28°22'7 for SUN LL,
what intercept do you find ?
Thanks for your Kind Attention and Best Regards
Kermit
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