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    Re: USCG Student Sample Problem #4
    From: Peter Hakel
    Date: 2013 Apr 27, 15:08 -0700
    Hi Kermit,

    My results are the same as yours:
    SD = 16.117'  (after removing the rounding); agrees with 16.1' from NA: 2013 Commercial Edition
    Intercept: 19.8' Away
    Azimuth: 126.2

    Cheers,


    Peter Hakel


    From: Antoine Couëtte <antoine.m.couette{at}club-internet.fr>
    To: pmh099---.com
    Sent: Saturday, April 27, 2013 1:16 PM
    Subject: [NavList] Re: USCG Student Sample Problem #4


    RE : http://fer3.com/arc/m2.aspx/USCG-Student-Sample-Problem-4-Rudzinski-apr-2013-g23703
    Hello Greg,

    You wrote :
    QUOTE
    My guess on the Sun difference of 0.2' would be the way rounding of semi diameter is done between your program and USNO.
    UNQUOTE
    I would surprised that USNO would make such a 0.2' rounding on the SUN Semi-Diameter which is very well known and changes very slowly. On my side, I do not round the SUN SD and do not use any Irradiation factor either. For this example I am using SD = 16'117 (same value as the 16'1 you have published).
    How about getting third party results ?
    Peter, Andrés or Yves (or others) ?
    From : Nov 01 st, 2013 at UT 22:59:53 / N 26° / E 143°55'3 , with HOE = + 100 ft , standard conditions and Sextant Height (already corrected for Instrument Error) equal to 28°22'7 for SUN LL,
    what intercept do you find ?
    Thanks for your Kind Attention and Best Regards
    Kermit
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