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RE : http://fer3.com/arc/m2.aspx/USCG-Student-Sample-Problem-4-Rudzinski-apr-2013-g23703

Hello Greg,

You wrote :

QUOTE

My guess on the Sun difference of 0.2' would be the way rounding of semi diameter is done between your program and USNO.

UNQUOTE

I would surprised that USNO would make such a 0.2' rounding on the SUN Semi-Diameter which is very well known and changes very slowly. On my side, I do not round the SUN SD and do not use any Irradiation factor either. For this example I am using SD = 16'117 (same value as the 16'1 you have published).

How about getting third party results ?

Peter, Andrés or Yves (or others) ?

From : Nov 01 st, 2013 at UT 22:59:53 / N 26° / E 143°55'3 , with HOE = + 100 ft , standard conditions and Sextant Height (already corrected for Instrument Error) equal to 28°22'7 for SUN LL,

what intercept do you find ?

Thanks for your Kind Attention and Best Regards

Kermit

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