NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Time of meridian passage accuracy
From: Peter Hakel
Date: 2009 Sep 25, 15:19 -0700
From: George Huxtable <george@hux.me.uk>
On the 29th April, the Sun's declination is increasing
(Northward) by about 0.8 arc-minutes per hour.
==============================================================================
If we define:
d: hourly rate of change of Sun's declination in arcminutes
D: number of days elapsed during the current year
a: "phase angle" ( a~0 at winter solstice, a~90 at vernal equinox, etc. )
a = {D+10} / 365 * 360 degrees
then the following approximate expression for "d" seems to work well enough:
d = 60 * 23.45 * SIN(a) * ( 360 / 365 ) / 24 * ( Pi / 180 )
For April 29 we have D=118 and hence d=0.8' per hour, just as George stated above.
Peter Hakel
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From: Peter Hakel
Date: 2009 Sep 25, 15:19 -0700
From: George Huxtable <george@hux.me.uk>
On the 29th April, the Sun's declination is increasing
(Northward) by about 0.8 arc-minutes per hour.
==============================================================================
If we define:
d: hourly rate of change of Sun's declination in arcminutes
D: number of days elapsed during the current year
a: "phase angle" ( a~0 at winter solstice, a~90 at vernal equinox, etc. )
a = {D+10} / 365 * 360 degrees
then the following approximate expression for "d" seems to work well enough:
d = 60 * 23.45 * SIN(a) * ( 360 / 365 ) / 24 * ( Pi / 180 )
For April 29 we have D=118 and hence d=0.8' per hour, just as George stated above.
Peter Hakel
--~--~---------~--~----~------------~-------~--~----~
NavList message boards: www.fer3.com/arc
Or post by email to: NavList@fer3.com
To , email NavList-@fer3.com
-~----------~----~----~----~------~----~------~--~---