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Further analysis of Huxtable's simulated observations shows that solving
for slope vs. using the known slope does make a difference -- if the
observations are not symmetrically distributed around the center time.

To test this, I picked three random observations in each set and
computed the altitude at the mid time (of the full data set) both ways.
Differences of a few tenths of a minute occurred.

Those are in the upper line under each data set, along with the
observations I used. The lower lines show what happens if the three
middle observations are used instead of randomly selected ones. In these
cases, "helping" the solution with the known rate of change made no
difference.


> First:
> 34º 16.7', 34º 21.0, 34º 25.4, 34º 32.0, 34º 38.6, 34º 46.3, 34º 49.9, 34º 
> 58.3, 34º 58.8.
#2, #6, #4: 6.325'/minute, 34º39.42' (6.0'/minute, 34º39.10')
#4, #5, #6: 7.150'/minute, 34º38.97' (6.0'/minute, 34º38.97')


> Second.
> 76º 29.7, 76º 39.2, 76º 42.8, 76º 48.2, 76º 57.8, 77º 03.1, 77º 05.9, 77º 
> 12.8, 77º 19.5.
#5, #8, #4: 5.885'/minute, 76º55.68' (6.0'/minute, 76º55.60')
#4, #5, #6: 7.450'/minute, 76º56.37' (6.0'/minute, 76º56.37')


> Third.
> 42º 47.3, 42º 53.3, 42º 54.9, 43º 05.8, 43º 12.4, 43º 16.9, 43º 24.4, 43º 
> 29.2, 43º 37.9.
#3, #2, #4: 6.250'/minute, 43º10.50' (6.0'/minute, 43º10.00')
#4, #5, #6: 5.550'/minute, 43º11.70' (6.0'/minute, 43º11.70')


> Fourth.
> 11º 18.0 , 11º 25.9, 11º 30.8, 11º 39.8, 11º 42.7, 11º 44.1, 11º 51.3, 11º 
> 58.6, 12º 05.3.
#3, #8, #1: 5.754'/minute, 11º41.55' (6.0'/minute, 11º 41.80')
#4, #5, #6: 2.150'/minute, 11º42.20' (6.0'/minute, 11º 42.20')

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