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    Re: A Sun-compass landfall?
    From: David Pike
    Date: 2021 Apr 16, 00:21 -0700

    Gary Lapook you wrote: I dangled my pencil over the pivot point on the protractor and observed where its shodow cut the arc and used that measurement for the coriolis correction. Z= .0262 X groundspeed (knots) X sin of latitude X sin of relative bearing. I assumed the normal cruising speed of jets of 450 knots. 

    That sounds and interesting way of doing it Gary.  We were taught to move our assumed position to the right or left of track depending on hemisphere a number of nm taken from Table 7 in AP3270 Vols 2&3 (Table 9 in Vol1).  For you, Coriolis' must have been about 8 or 9nm right of track. DaveP

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