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    Re: Spherical triangle split by right triangles
    From: Ron Jones
    Date: 2016 Jan 22, 19:47 -0800

    NASR Triangles Formulas
     
    Triangle I:
    sin(A) = sin(LHA)·cos(L)
    sin(B) = cos(L)·sin(Z1)
    cos(LHA) = sin(Z1)·cos(A)
    sin(L) = cos(A)·cos(B)
    cos(Z1) = sin(LHA)·cos(B)
    sin(A) = tan(90°-Z1)·tan(B)
    sin(B) = tan(A)·tan(90°-LHA)
    sin(LHA) = tan(B)·tan(L)
    sin(Lat) = tan(90°-LHA)·tan(90°-Z1)
    sin(Z1) = tan(L)·tan(A)
     
    Triangle II:
    sin(A) = cos(H)·sin(P)
    cos(F) = cos(H)·sin(Z2)
    cos(P) = sin(Z2)·cos(A)
    sin(H) = cos(A)·sin(F)
    cos(Z2) = sin(P)·sin(F)
    sin(A) = tan(90°-Z2)·tan(90°-F)
    cos(F) = tan(90°-P)·tan(A)
    cos(P) = tan(90°-F)·tan(H)
    cos(H) = tan(90°-Z2)·tan(90°-P)
    cos(Z2) = tan(A)·tan(H)



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