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    R: Re: R: Solutions to Gray's 100 Problems (Problem 1-1)
    From: Federico Rossi
    Date: 2007 Sep 27, 08:07 +0200

    I used a single assumed position since you don't need an even degree LHA
    with the haversine method.
    -----Messaggio originale-----
    Da: NavList@fer3.com [mailto:NavList@fer3.com] Per conto di
    Inviato: gioved� 27 settembre 2007 1.56
    A: NavList
    Oggetto: [NavList 3277] Re: R: [NavList 3275] Solutions to Gray's 100
    Problems (Problem 1-1)
    Did you measure these from a single assumed position, or did you use
    different assumed positions for each sight. I did the latter, taking
    the longitude minutes of my assumed positions to equal those from the
    almanac table. I understand that using a calculator or computer, one
    does not need even degrees to do sight reduction as is done with the
    On Sep 26, 4:31 pm, "Federico Rossi" 
    > Hi,
    > I've just found my notebook with the solutions to the problems.
    > I worked the sights with the classical haversine method and got the
    > following intercepts:
    > Kochab -1.9 Az 339
    > Rasalhague -14 Az 233
    > Alkaid -5.6 Az 311
    > Altair -4.1 Az 176
    > Venus +10.1 Az 97.5
    > Moon +4.4 Az 150
    > This gave me a fix at 40 13.5 N 49 58.5 W, which is practically identical
    > the solution given by the book.
    > Hope this can help.
    > Federico
    > -----Messaggio originale-----
    > Da: NavList@fer3.com [mailto:NavList@fer3.com] Per conto
    > Parsa
    > Inviato: gioved� 27 settembre 2007 0.22
    > A: NavList
    > Oggetto: [NavList 3275] Solutions to Gray's 100 Problems (Problem 1-1)
    > Hi, I'm new to the list.
    > Speaking of the moon... I am working through Leonard Gray's book One
    > Hundred Problems in Celestial Navigation. I calculated and plotted all
    > the sights for the stars, the moon's lower limb, and Venus for the
    > first problem (1-1). My solutions for the stars and Venus seem OK, but
    > my line-of-position for the moon seems quite a ways off. I get a
    > pretty good solution without the moon (not more than one minute off of
    > the given answer, and that's using an 8.5 x 11 plotting sheet).
    > Is there anyone that has saved their solution to this in notes
    > somewhere? I would like to see if it is supposed to be so far off, or
    > if I left out one of the many corrections for the moon. The stars
    > using Pub 249 were sure much easier!
    > Secondly, does anyone know of any online celnav worksheet forms? I
    > downloaded the ones by Harold Arsem from the celestialnavigation.net
    > website, but I thought I would find more on the internet than just a
    > couple forms.
    > Parsa
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