Welcome to the NavList Message Boards.

NavList:

A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding

Compose Your Message

Message:αβγ
Message:abc
Add Images & Files
    or...
       
    Reply
    Re: Smart and Shearme Position Line Tables
    From: Lars Bergman
    Date: 2020 May 5, 11:59 -0700

    As DaveP said, there are two possible solutions to

    cos(azimuth - x) = cot(latitude)·tan(altitude)·cos(x),  where tan(x) = csc(latitude)·cot(hour angle)

    As cos(azimuth - x) = cos(x - azimuth) you get azimuth = x ± arccos[cot(latitude)·tan(altitude)·cos(x)], and x is the angle at zenith between the observer's meridian and a perpendicular to the body's meridian.

    Lars

       
    Reply
    Browse Files

    Drop Files

    NavList

    What is NavList?

    Join NavList

    Name:
    (please, no nicknames or handles)
    Email:
    Do you want to receive all group messages by email?
    Yes No

    You can also join by posting. Your first on-topic post automatically makes you a member.

    Posting Code

    Enter the email address associated with your NavList messages. Your posting code will be emailed to you immediately.
    Email:

    Email Settings

    Posting Code:

    Custom Index

    Subject:
    Author:
    Start date: (yyyymm dd)
    End date: (yyyymm dd)

    Visit this site
    Visit this site
    Visit this site
    Visit this site
    Visit this site
    Visit this site