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    Re: Request for simple trig formula
    From: Sam Chan
    Date: 2003 Apr 15, 18:19 -0700

    Law of Cosine (good for non-right triangles)
    Let A, B, and C be the three angles of a triangle. Let a, b, and c be the
    lengths of the "opposite" side.
    The Law of Cosine:  c^2 = a^2 +b^2 -2a*b*cos(C)
    For right triangles: Let C be the right angle. The long side opposite of C
    is called the hypotenuse. From any non-right angled corner,
    sin A = a/c  where a is the length of the side opposite of the angle A and c
    is the hypotenuse
    cos A = b/c where b is the length of the side adjacent to the angle A and c
    is the hypotenuse
    Use either of these to find angle A.
    Once angle A is found, angle B =90-A.
    ----- Original Message -----
    From: "David Weilacher" 
    Sent: Tuesday, April 15, 2003 3:03 AM
    Subject: Request for simple trig formula
    > I need a favor.
    > I don't recall the simple trig formulas and don't have the mental
    where-with-all to find anything using a search engine.  I think it is
    because my mind just doesn't index the way they do.
    > If I know the lengths of 3 sides of a triangle and one angle (90), how do
    I determine the two remaining angles.
    > I do own a fancy calculator capable of sin, cos stuff.
    > What I would like to come away with are the side-angle-side,
    angle-side-angle, and side-side-side formulas so that I can write them down
    in my address book for future reference.
    > Thank you.
    > PS: I am attempting to solve a problem indirectly related to navigation.
    > Dave Weilacher
    > .US Coast Guard licensed captain
    > .    #889968
    > .ASA instructor evaluator and celestial
    > .    navigation instructor #990800
    > .IBM AS400 RPG contract programmer

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