A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
From: Peter Hakel
Date: 2011 Jan 2, 23:40 -0800
Thank you for these data sets.
For the first set of your Venus data I get the following averages:
UT = 9:16:54
Ho = 10d 27.7'
with sight #3 practically eliminated (relative weight 0.8%). Your data nicely fall on a straight line, but upon closer look one does see #3 displaced a tiny little bit. I added the plot to visualize the data after the calculation was finished.
Lat N 14d 25'
Lon W 55d 00'
I get intercept 0.7A and azimuth 102.7.
From: Gary LaPook <email@example.com>
Sent: Sun, January 2, 2011 10:20:44 PM
Subject: [NavList] Re: Rejecting outliers
|Let me add that the temperature was about 70 F. I don't know what the barometric pressure was but the weather was fair so there is no reason to believe that the pressure was out of the ordinary. The pilot chart for October shows the average pressure in that area is 1013 mb. |
--- On Sun, 1/2/11, Gary LaPook <firstname.lastname@example.org> wrote: