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    Re: Regarding fix bearings
    From: Gary LaPook
    Date: 2008 Dec 21, 01:59 -0800

    It looks like the classic "double the angle on the bow" technique. I am
    attaching Dutton's explanation.
    
    Another method is taught to every instrument rated pilot. With the
    station near the wing tip (near the beam if talking about ships) measure
    the time it takes for a certain number of degrees of bearing change in
    seconds. Then divide the seconds by the number of degrees of bearing
    change and the result is the distance to the station in minutes. This
    works because the tangent of  one degree is approximately equal to 1/60
    and this approximation holds true for small angles.
    The actual formula is (time/degrees of bearing change) x 60 = time to
    the station. By measuring the time in seconds the multiplication by 60
    is accomplished automatically when you take the result in minutes. The
    formula can also be worked to find distance. Simply measure the time in
    minutes and multiply by your speed in knot, then divide by the number of
    degrees of bearing change to give you your distance off in nautical
    miles. Measuring in minutes and multiplying by your speed takes care of
    the internal multiplying  by 60. In flying the bearings are measured
    with and ADF or VOR but the same technique works with visual bearings.
    
    A simple example. Say it takes 120 seconds for the bearing to change 10
    degrees. 120/10 = 12 minutes to the station. The same example, 120 knots
    times 2 minutes divided by 10 puts you 24 NM from the station. This is
    the same result as multiplying the 120 knot speed by 12 minutes divided
    by 60 minutes per hour. I have attached an excerpt from FM 1-240 that
    illustrates this.
    
    gl
    
    George Huxtable wrote:
    > inuik@yahoo.com, or A-08, wrote the posting copied below.
    >
    > That idea sounds original, simple, and interesting.
    >
    > Tell us more, A-08.
    >
    > George.
    >
    > contact George Huxtable, at  george@hux.me.uk
    > or at +44 1865 820222 (from UK, 01865 820222)
    > or at 1 Sandy Lane, Southmoor, Abingdon, Oxon OX13 5HX, UK.
    >
    >
    > ----- Original Message -----
    > From: 
    > To: 
    > Sent: Saturday, December 20, 2008 2:12 AM
    > Subject: [NavList 6773] Regarding fix bearings
    >
    >
    > |
    > | Regarding fix bearings: A convenient practice of taking two bearings at
    > one landmark is to take the first bearing at 45 deg, then second bearing is
    > taken off beam (90 deg).  In this case distance off beam is equal distance
    > traveled.
    > | There are also few so-called "magic" angles which play the same trick:
    > upon using them distance travelled is equal distance off.
    > |
    > | I wrote a formula which permits for the first bearing chose any angle you
    > want and then calculate the angle for the second bearing which, as a result,
    > equals distance travelled to distance off.
    > |
    > | I think it gives some flexibility in bearing taking and especially in
    > calculating distance off.
    > |
    > | Respectfully,
    > |
    > | A-08
    > |
    > |
    > | ------------------------------------------
    > | [Sent from archive by: inuik-AT-yahoo.com]
    >
    >
    > >
    >
    >
    
    
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