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    Re: Q: how to calculate refraction at higher altitudes on land?
    From: Dov Kruger
    Date: 2002 Feb 28, 16:16 -0500

    Craig wrote:
    
    >I was thinking, in using trigonometry to solve a right triangle, you know
    >the adjacent side from your GPS (Difference between your lat/lon position
    >and lat/lon of mountain peak.  You measure the angle, can get the tangent,
    >and solve for the opposite side, which is the difference between height of
    >mountain peak and your height.  Subtract length of oppposite side from
    >mountain peak height, doesn't that give you your height?
    >Tangent=opposite/adjacent, therefore opposite=tangent*adjacent.
    >
    My mistake, you are right.
    Dov
    
    
    

       
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