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A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Q: how to calculate refraction at higher altitudes on land?
From: John Kabel
Date: 2002 Feb 28, 13:11 -0500
From: John Kabel
Date: 2002 Feb 28, 13:11 -0500
Has anyone in your area sold a house or property lately? They may have had a survey done. This should have an elevation on it for a nearby monument. Then you work from there with your sextant(s) and an artificial horizon. Just a suggestion ... The neighbours might be keen to participate in the project. John Kabel London, Ontario > I am specifically trying to determine the elevation of my house. > > The topographic maps of my area are decades old. They do not show > our streets or houses, and in fact the area has been graded to some > extent as well, so even finding my exact location via GPS and then > looking on the map only gives a ballpark figure. > > Since SA has been turned off, the GPS gives a range of elevations > from 580 feet to 650 feet. The Garmin GPS 3 tends to wander over > this range. I am trying to get a better value. > > I have a high quality Chelsea barometer, a Garmin GPS, and many > sextants. I have high mountains behind my house, lots of clouds, > and the only kind of horizon I'll ever see is an artificial one. > In the winter, the sun comes up behind the mountain at about 11AM > and goes down about 12:30PM! > > Given these constraits and tools, can I get a better estimate of > my elevation? > > > -----Original Message----- > From: Navigation Mailing List > [mailto:NAVIGATION-L@LISTSERV.WEBKAHUNA.COM]On Behalf Of Dov Kruger > Sent: Thursday, February 28, 2002 7:41 AM > To: NAVIGATION-L@LISTSERV.WEBKAHUNA.COM > Subject: Re: Q: how to calculate refraction at higher altitudes on land? > > > Oops! > Dan, > > At high angles (above 45 or so) you will have so little refraction in > the first place that any reduction in it won't make a significant > difference with what I originally said. You can just do your atmospheric > correction and that's more than it deserves. But at the lower angles, > the normal correction for pressure will presumably be too great, because > the reason the pressure is low is that you are high, not because your > whole region is experiencing low pressure. > > In the worst case, consider you are looking down at the horizon. Near > the horizon, your line of sight is passing through sea-level air. > Halfway, it is passing through air at half your altitude. Since the > correction is small in any case, why not just try to divide it in half > and use that? You know the upper bound (no pressure correction) and the > lower bound (full pressure correction) so you know exactly how bad your > assumption can be. > > Why not send us the raw data when you do it so we can take a look? > > cheers, > Dov