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    Re: Q: how to calculate refraction at higher altitudes on land?
    From: Dan Allen
    Date: 2002 Feb 28, 15:23 -0800

    Great ideas all!  I'll have to do the barometer experiment (the ocean
    is less than an hour away), and I'll also mess around with measuring
    the angle to the top of Rattlesnake Ridge, the mountain south of my
    house.
    
    Dan
    
    -----Original Message-----
    From: Navigation Mailing List
    [mailto:NAVIGATION-L{at}LISTSERV.WEBKAHUNA.COM]On Behalf Of Craig
    Sent: Thursday, February 28, 2002 12:41 PM
    To: NAVIGATION-L{at}LISTSERV.WEBKAHUNA.COM
    Subject: Re: Q: how to calculate refraction at higher altitudes on land?
    
    
    I was thinking, in using trigonometry to solve a right triangle, you know
    the adjacent side from your GPS (Difference between your lat/lon position
    and lat/lon of mountain peak.  You measure the angle, can get the tangent,
    and solve for the opposite side, which is the difference between height of
    mountain peak and your height.  Subtract length of oppposite side from
    mountain peak height, doesn't that give you your height?
    Tangent=opposite/adjacent, therefore opposite=tangent*adjacent.
    
    
    

       
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