NavList:

   

Reply

A tip o' the hat to that. Bless the gods for sines, cosines and
calculators.  Hewitt

On 12/2/09, John Karl  wrote:
>
>  > As I read it, what Guus seems to be asking is how they got the
>  > additional .2'  they added to the course from the AP (246.1�) to the
>  > course from the actual point of departure in Fremantle (246.3�).
>  >
>  > Hewitt
>
>
> Yep, I think you're right.  I hadn't paid any attention to parts (4)
>  to (6) below the example.
>
>  Part (6) requires a triple interpolation of Z among dec, LHA, and
>  lat.  I skipped the lat interpolation because the 32*03' departure lat
>  is so close to 32*.  Then my double interpolation of Z for LHA and dec
>  gives me 66.25* rounding to the 66.3* on page XXI of H.O. 229.
>
>  All this is pretty darn academic compared to actual practice at sea --
>  at least in my experience.
>
> JK
>
>  --
>  NavList message boards: www.fer3.com/arc
>  Or post by email to: NavList@fer3.com
>  To , email NavList+@fer3.com

-- 
NavList message boards: www.fer3.com/arc
Or post by email to: NavList@fer3.com
To , email NavList+@fer3.com

   

Reply