NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Pub.229 GC-Calculation distance and course.
From: Hewitt Schlereth
Date: 2009 Dec 2, 08:28 -0400
From: Hewitt Schlereth
Date: 2009 Dec 2, 08:28 -0400
As I read it, what Guus seems to be asking is how they got the additional .2' they added to the course from the AP (246.1�) to the course from the actual point of departure in Fremantle (246.3�). Hewitt On 12/1/09, John Karlwrote: > Guus, > > I don't understand the 0.2* that you're talking about. The Z > interpolation is for the dec between 29* and 30*, the desired Z being > for dec = 29* 52'. So the Z interpolation calculation is 52'/60' X > 0.9* = 0.8*, giving Z = 66.9* - 0.8* - 66.1* as in the book. > > Make sense? > > JK > > > -- > NavList message boards: www.fer3.com/arc > Or post by email to: NavList@fer3.com > To , email NavList+@fer3.com -- NavList message boards: www.fer3.com/arc Or post by email to: NavList@fer3.com To , email NavList+@fer3.com