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    Re: Position from altitude and azimuth.
    From: Andrés Ruiz
    Date: 2020 May 8, 12:26 +0200
    Hello dear Dave,

    solution by several methods.
    For iterative ones, assuming my location as initial value.

    06/05/2020
    15:00:00

    Bap = 43.316667 º =  43º 19.0'
    Lap = -2.000000 º =  -2º  0.0'

    NAUTICAL ALMANAC
    Sun
    GHA = 45.852082 º =  45º 51.1'
    Dec = 16.779705 º =  16º 46.8'
    SD = 15.8518 '
    HP = 0.1453 '

    One Body Fix by HZ
    Hc = 54.9317 º =  54º 55.9'
    Zn = 120.5 º
    LHA = 43.852082 º =  43º 51.1'

    Fix PositionByAltitudeAndAzimuth
    B = 38.995304 º =  38º 59.7'
    L = -77.003888 º = -77º  0.2'

    Fix PositionByAltitudeAndAzimuthJK
    B = 38.995304 º =  38º 59.7'
    L = -77.003888 º = -77º  0.2'

    Fix Differential Equation
    B = 38.995304 º =  38º 59.7'
    L = -77.003888 º = -77º  0.2'

    Fix Differential Equation Z(B,L,H)
    B = 38.995304 º =  38º 59.7'
    L = -77.003888 º = -77º  0.2'

    DifferentialEquation
    iter B L Zo Zc
    0 42.3166667 -3 120.454833 248.30433
    1 121.066944 -59.0866311 120.454833 166.971806
    2 56.9215911 -110.235393 120.454833 102.366695
    3 25.5650641 -72.1148913 120.454833 104.566047
    4 36.8059639 -79.3110093 120.454833 115.111147
    5 39.170917 -77.1117691 120.454833 120.54137
    6 38.9949739 -77.0041267 120.454833 120.454143
    7 38.9953037 -77.0038875 120.454833 120.454833
    DifferentialEquationBLH
    iter B L Zo Zc
    0 42.3166667 -3 120.454833 248.30433
    1 121.066944 -59.0866311 120.454833 166.971806
    2 56.9215911 -110.235393 120.454833 102.366695
    3 25.5650641 -72.1148913 120.454833 104.566047
    4 36.8059639 -79.3110093 120.454833 115.111147
    5 39.170917 -77.1117691 120.454833 120.54137
    6 38.9949739 -77.0041267 120.454833 120.454143
    7 38.9953037 -77.0038875 120.454833 120.454833

    Fair winds and following seas.
    --
    Andrés Ruiz
    Navigational Algorithms
    http://sites.google.com/site/navigationalalgorithms/
       
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