NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
From: Wolfgang Köberer
Date: 2008 Jul 30, 15:16 +0200
Yesterday I received "The Navigator's
Newsletter" issue 97 - 99. The last issue contains an article by David
Burch (from his book "Emergency navigation") about "Photo
sextant sights". As this had been discussed on the list not too long ago I
read the article right away. It relates the example of a "Photo sextant
sight" taken in
Now being in the legal profession I lack the
knowledge or the brains (or both) to invent new methods of celestial
navigation, but like to try their practical usefulness. The article sums up:
"had we not known time or longitude, we would have found our longitude
this way to within 53 min ". This would mean a possible error of about 47
miles - which is probably acceptable.
Then I did a quick "Sumner": I varied the
input to see what happens to the result. On the assumption that there is no
error in latitude (having bent my sextant only after taking the height of
Polaris or a star on the meridian) and that my time is correct, I varied my assumed
longitude and got a perplexing result: Using Frank's program and assuming I am about
150 miles out in the Atlantic (= assumed longitude 77deg 10 min W) I got the
following result:
"Error in Lunar: 0 min
Approximate Error in Longitude: 0 deg 00.4 min"
which - following David Burch – I interpret as
saying I am almost at my assumed position. As the "Photo Sextant
Sight" supposedly was taken 3 degrees further west something doesn't fit. What
did I get wrong? It's not the input, I checked it several times.
Dr.
Wolfgang Köberer
Wolfsgangstr. 92
D-60322 Frankfurt am Main
Tel:
+ 49 69 95520851
Fax: + 49 69 558400
e-mail: koeberer@navigationsgeschichte.de
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