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    Re: Noonsite using artificial horizon? Did I do it correctly?
    From: Hewitt Schlereth
    Date: 2014 Aug 28, 11:55 -0700
    OOPS!!! Sorry guys. This was a reply to a pal re a Star Trek actors reunion.

    I wonder what the heck he got?

    FWIW Here's the Trek link:


    On Aug 28, 2014, at 10:31 AM, "Hewitt Schlereth" <NoReply_Schlereth@fer3.com> wrote:

    Aren't they cute. But where is 7-of-9?

    On Aug 28, 2014, at 9:56 AM, "Brad Morris" <NoReply_Morris@fer3.com> wrote:

    You wrote
    Does 1.6' minutes mean 1'12"

    No sir.

    If 1' = 60", then 0.6'= 36".

    So 1.6' = 1'36"

    On Aug 28, 2014 3:47 AM, "Samuel L" <NoReply_SamuelL@fer3.com> wrote:

    Gary,

    I just 6 Sun shots over the past hour with some success in getting close to the correct Hc using the USNO Celestial Navigation website. I was off between 1 to 2 minutes or so. Sights were taken using an Artficial Horizon and used the Lower Limb of the Sun and the Upper Limb of the Sun from the reflected image off of the AH.

    Here's what I did;

    Subtract IE (Index Error). For my sextant the error is 4' above the mark to subtract the 4'.

    - Took the sight and recorded the time and Hs

    - SUBTRACTED IE

    - Divided the answer by 2

    - added (or subtracted) Refraction based on answer above (after dividing the Hs minus IE divided by 2.

    - added SemiDiameter

    The resulting answer is the Hc

     

    Does figure like 1.6' really mean 1' 12"  ???

    It's difficult figuring out the "tenths" of a minute using my calculator.

     

     

     

     

       
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