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The derivation of the equations in "POSITION FROM OBSERVATION OF A SINGLE BODY 
James N. Wilson Vol. 32, No. 1, 1985" is totally general, and under the 
conditions George says, they must work.

For the simulation in [NavList 5794], I have used the simplified formula:
 Sn = V * DCOS(R)
 d = dDecdt
 TimeOfLANcorrection = 48# / PI * (Sn - d) * (DTAN(B) - DTAN(Dec))


But for this simulation I have used the general one, because a component of 
the course in the N-S and E-W axis appears:
 V = V / 60#
 Sns = V * DCOS(R)
 Sew = V * DSIN(R)

 dBdt = Sns
 dLdt = Sew / DCOS(B)
 dLHAdt = dGHAdt + dLdt
 
TimeOfLANcorrection2 = 3600# * 180# / PI * (dBdt - dDecdt) * (DTAN(B) - DTAN(Dec)) / (dLHAdt * dLHAdt)

The solution is t LAN: 15:36:51 from data and form James equation!!!

Andrés


-----Mensaje original-----
De: NavList@fer3.com [mailto:NavList@fer3.com] En nombre de George Huxtable
Enviado el: viernes, 11 de julio de 2008 17:32
Para: NavList@fer3.com
Asunto: [NavList 5798] Re: Noon sight for longitude


Andres Ruiz wrote-
...
Andres' simulation would be interesting when applied to a latititude of say 
53ºN, with a declination of -23º, when a low noon Sun makes things more 
difficult..
...

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