NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: No Two-Body Fix Problems
From: Peter Hakel
Date: 2009 Nov 6, 13:08 -0800
From: George Huxtable <george@hux.me.uk>
To: navlist@fer3.com
Sent: Fri, November 6, 2009 12:29:42 PM
Subject: [NavList 10476] Re: No Two-Body Fix Problems
[parts deleted by PH]
He and I seem to be agreeing about the existence
of the same problem, here, though we may be proposing to resolve it in
different ways. In what way was it explicitly addressed? Was that by the
cross-check against zenith distance of star2?
------------------------------
That is correct.
=================
This leaves aside another matter; whether the cosine formula is indeed the
best way to determine LHA, when the LHA is a small angle? Wouldn't the sine
formula be more appropriate, then? That would spoil John's claim that he
only ever used the one basic formula, however.
------------------------------
This brings up the haversine function: hav(x) = sin^2(x) = (1 - cos(x) ) / 2.
I tried it and it does help with the ACOS() problem, thanks for the suggestion.
Peter Hakel
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From: Peter Hakel
Date: 2009 Nov 6, 13:08 -0800
From: George Huxtable <george@hux.me.uk>
To: navlist@fer3.com
Sent: Fri, November 6, 2009 12:29:42 PM
Subject: [NavList 10476] Re: No Two-Body Fix Problems
[parts deleted by PH]
He and I seem to be agreeing about the existence
of the same problem, here, though we may be proposing to resolve it in
different ways. In what way was it explicitly addressed? Was that by the
cross-check against zenith distance of star2?
------------------------------
That is correct.
=================
This leaves aside another matter; whether the cosine formula is indeed the
best way to determine LHA, when the LHA is a small angle? Wouldn't the sine
formula be more appropriate, then? That would spoil John's claim that he
only ever used the one basic formula, however.
------------------------------
This brings up the haversine function: hav(x) = sin^2(x) = (1 - cos(x) ) / 2.
I tried it and it does help with the ACOS() problem, thanks for the suggestion.
Peter Hakel
--~--~---------~--~----~------------~-------~--~----~
NavList message boards: www.fer3.com/arc
Or post by email to: NavList@fer3.com
To , email NavList+@fer3.com
-~----------~----~----~----~------~----~------~--~---