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Here's my attempt.  I calculated from first principles using the
nautical almanac.

2006 Nov 11
4h 17m 31s GMT
Lat=17d 38.6m N
Long=1452d 22.7m E
Dec=17d 22.1m S

Az by gyro 223.0
Heading by gyro 125d
Mag compass 110d
Variation 0.2d W

My results were

LHA=30.76  2h 3.06m
Az=222.488  222d 29.3m
Gyro compass error=30.7m E

C=110d
D=14d 41.3m E (add)
M=124d 41.3m
V=12.0m W (subtract)
T=124d 29.3m

John Cole


On May 24, 12:16�am, Anabasis  wrote:
> Since we have a recent post and some discussion of checking the
> compass at sea, here is an example of a afternoon Azimuth of the sun I
> shot while underway from South Korea to Saipan, CNMI:
>
> Azimuth of the Sun
>
> On 11 November 2006, a ship was in position Latitude 17 deg 38.6�
> North, Longitude 142 deg 22.7� East. �At 04h 17m 31s UTC, a gyro
> bearing was taking of the sun. �The observed gyro azimuth was 223.0
> degrees. �The ship�s heading was 125 deg per gyro compass, and 110
> degrees per magnetic compass. �Local Variation was 0.2 deg West.
> Determine the Gyro compass error, magnetic compass error and deviation
> of the magnetic compass at that heading.
>
> As usual, I will standby for any questions and will post my reduction
> in a day or two. �Please note how you came about your answer. �Did you
> use tables, if so, which ones? �Was it a calculator, computer etc?
>
> Thanks, and have fun!
>
> Jeremy
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