NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Lunars using Bennett
From: Frank Reed
Date: 2008 Apr 06, 20:21 -0400
From: Frank Reed
Date: 2008 Apr 06, 20:21 -0400
Peter, you wrote: "The next column shows the difference, and at the bottom of that column the standard deviation is displayed: 0.7. Excel file attached. If I've understood correctly, the standard deviation should approximate 1.22 (0.5xsqrt6)." Your result, 0.7, is just right. It's not 1.22, because the "step size" for this random walk is not constant. In a textbook random walk, you would have N steps of equal size A. Then the expected distance after N steps is A*sqrt(N). In the case of adding up numbers rounded to the nearest whole number, the step size is 0.5 at most, but it's not constant and, on average, it's smaller. In fact, what we need is the standard deviation of a uniform distribution one unit wide ("uniform" since the fractional difference can fall anywhere in the range from -0.5 to +0.5 with equal probability) and that happens to be 0.288. And 0.288*sqrt(N) with N=6 is 0.7 just as you found. It works. Now in a navigation problem things are rarely this simple, so you couldn't directly apply this result, but the general principle is the same. -FER --~--~---------~--~----~------------~-------~--~----~ Navigation List archive: www.fer3.com/arc To post, email NavList@fer3.com To , email NavList-@fer3.com -~----------~----~----~----~------~----~------~--~---