# NavList:

## A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding

**Re: Lunars - Even Easier**

**From:**Dan Allen

**Date:**2008 Jul 6, 22:44 -0600

Frank, I am impressed. Great advances simplify things and this is quite a simplification.

-- Dan

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-- Dan

On Wed, Jul 2, 2008 at 5:24 PM, <frankreed@historicalatlas.net> wrote:

The LD was 85. The Sun's zenith distance was 45. So if we force the Moon's

George, you wrote:

"I don't see the basis on which he decided to replace an observed zenith

distance for the Moon of 38 degrees by one of 40 degrees. Where did that

value of 40 come from?"

zenith distance to be 40, then the sight is perfectly aligned through the

zenith because that's the only case where the sum of the zenith distances

would be equal to the angle between the objects. And when that happens, the

triangle is degenerate so we don't need any trig to clear the sight which is

of course the goal of all this. Sounds crazy, right? It works because the

altitude of the Moon really doesn't matter much at all under some

circumstances, so we can introduce an "error" with very little downside

which converts the problem into a simple case.

Let's do a realistic example. Let's take the lunar observation we've all

been talking about (Jeremy's observation on June 10) and move the observer

to another location. Instead of being at 15º 14'N DR latitude, we move him

to 25º 14'N. But all of the other setup conditions remain the same. We keep

the DR longitude, temperature/pressure, date and time of observation exactly

the same. That way we don't have to look up a lot of new almanac data. You

can see that the Moon and Sun from that location would no longer

be as nicely aligned. In fact, at that time, their difference in azimuth

would amount to 155º --a good distance away from being aligned in opposite

azimuths, and clearly out of line even to a casual observer.

From the shifted DR, our observer takes these sights at 06:23:00 GMT:

Sun LL 35º 38'

Moon UL 56º 14'

LD Near 85º 40.3'

If you clear this lunar observation, you will find that it is exactly

correct for that time and location. I've set it up that way. Run it through

the lunar distance calculator at www.HistoricalAtlas.com/lunars, and you

will get error=0.0'.

Now let's see if we can adjust this observation and turn it into a simple

lunar with no trig required. We need the observed altitudes of the objects

centers above the true horizon, and we need the observed center-to-center

lunar distance (this is the normal "pre-clearing" step):

Sun LL: 35º38' -10'+16' = 35º 44'

Moon UL: 56º14' -10'-16' = 55º 48'

LD Near: 85º40.3' +15.8' +15.7' = 86º 11.8'

And now we add these up. The total is 177º 43.8'. It doesn't total 180º

because the objects are not aligned in opposite azimuths. And HERE is where

we apply the trick. If we raise the Moon's observed altitude by 2º 16.2'

then, of course, the total WOULD add up to 180º, and as far as the math is

concerned, this means they're now in opposite azimuths. So let's do that...

We work the same lunar observation again, but this time with a Moon UL

altitude of 58º 30.2'. If you do it by any of the standard spherical

triangle approaches, you will find that this modified observation has an

azimuth difference of very nearly 180º. And when we clear this modified

observation, the results are almost exactly the same. The error this time

around is 0.1'. But the important point is that we don't need to use any

spherical trig to solve a degenerate triangle. It reduces to a very simple

case of addition and/or subtraction.

There is one calculation we need to do. We need to make sure that it's

legitimate to shift the Moon's altitude by more than two degrees (legitimate

in the sense that the error introduced is within tolerable limits --the

exact limits of what is "tolerable" depends on the end-user). So we

calculate (6')*tan(LD)/cos(Moon_alt). In this case, this gives 173', nearly

three degrees, so modifying the Moon's altitude should not introduce an

error larger than a tenth of a minute of arc, and sure enough, that's what

we have already found.

Imagine if they had known about this 225 years ago. Back then, a somewhat

larger error in clearing might have been counted as "tolerable". A really

large number of lunar observations could have been reduced to simple cases

of addition or subtraction. The calculational work would have taken five

minutes at most...

Oh well. Can't change history!

-FER

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