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    Re: Lunar trouble, need help
    From: Kent Nordstr�m
    Date: 2008 Jun 22, 11:11 +0200

    George Huxtable wrote � I don't see what Sun's apparent time has to do with 
    the matter, or MT, or longitude. The aim of a lunar is to establish GMT, to 
    set a local clock
    right; nothing more than that. Steven's web page of lunar predictions is 
    marked as being for UT (= GMT), unlike the early almanacs, which until 1834
    were based on Greenwich Apparent Time. Kent's predictions must also be for 
    GMT, so I suggest he is bringing in complications that don't exist...�
    
    
    
    I don�t know if I complicate things or not, that was certainly not my 
    intention. My own view is that finding the GMT is of course interesting, 
    whatever means are used, but even more interesting is it to be able to find 
    own ship�s position in Lat. and Long. Finding a ship�s position at any time 
    is indeed the very objective for navigation. It was therefore I commented 
    not only the GMT but also the corresponding position in longitude (only) by 
    using the apparent time of the sun etc. My predictions of GMT incl. The 
    correction for 2.nd differencies are based on GMT while my predictions of MT 
    are based on sideral time converted to MT.
    
    
    
    Georg Huxtable wrote� I've had a go at working that lunar in my own way; 
    which means that I like to get out of those damned sexagesimals and into 
    decimals, so I can use my calculator properly. I will spell it all out in 
    more detail than if I were just calculating for myself.�
    
    
    
    I would like to comment this and also Geroge�s calculations. Firstly I hope 
    we agree that it is the mean time for the LD observation that has to be used 
    as reference for calculating altitudes of (in this case) the moon and the 
    sun. The mean time for LD observation was 06-22-59 (type of time still not 
    completely clear to me). If I then refer the moon�s and the suns� altitude 
    to this time I get the following:
    
    
    
    Moon:
    
    2.nd obs.       06-26-28               61d 49,2m
    
    1.st obs.        06-20-13               60d 36,8m
    
    Difference      00-06-15 (375 s)   1d 12,4m (72,4m)
    
    Elapsed time 1.st obs to mean LD= 2m 46s=166s
    
    Moon�s altitude 60d 36,8m+72,4*166/375=61d 08m 24s (George 61d 05m 16s)
    
    My data stated before was 61d 19m 18s. Wrongly calculated by me. Sorry for 
    any inconveniance caused.
    
    Sun:
    
    2.nd obs.       06-25-19               32d 35,8
    
    1.st obs         06-19-13               33d 58,5
    
    Difference      00-06-06 (366 s)   -1d 22,7 (82,7m)
    
    Elapsed time 1.st obs to mean LD=3m 46s=226s
    
    Sun�s altitude 33d 58,3m+82,7*226/366=33d 7m 24s (George same)
    
    
    
    Furhermore some comments and comparisons to George�s data:
    
    Moon:
    
    Dip -10m 11s (George -0,1667 =10m)
    
    Refr -29,5m (George -0,083=4m 58,8s)
    
    It is not clear to me how George�s refraction has been calculated.
    
    SD -15m 25s (George -(0,2606-0,0035)=15m 25,6s)
    
    Augmentation   -13,34s (George � 0,0035= -12,6s) 
    A
    
    Corr for refr. Edge-centre -0,34s (George none)
    
    Parallax +27m 30s (George +0,4622=27m 36,7s)
    
    I wonder if George�s calculation of the moon�s parallax considers earth 
    flattening. I do not follow the correction of -0,002 =-7,2s, however with 
    this included we reach the same parallax.
    
    Altitude 61d 10m 11,6s (George 61 06m 51,5s)
    
    For the sun it seems that we have reached the same altitude, anyway I don�t 
    understand George�s data on refraction (seems to be the same as for the 
    moon). My refraction for the sun is -1m 21,02s.
    
    
    
    Calculated d= 86d 41m 28,1s. Nearest edges used. (George 86,1698 =86d 10m 
    11,3s)
    
    
    
    Calculated D=86d 15m 00,3s (George 85,7384 =85d 44m 18,2s)
    
    
    
    GMT 07-26-52,9 (George 06-24-53). This difference depends of course on how 
    the LD�s were measured. However the method for measurement by �overlapping� 
    edges does not convince me. It seems to be a construction afterwards.
    
    
    
    2nd diff 00-00-5,6s (George none)
    
    
    
    Corrected GMT 07-26-47,3
    
    Kent N
    ----- Original Message ----- 
    From: "George Huxtable" 
    To: 
    Sent: Friday, June 20, 2008 12:30 PM
    Subject: [NavList 5530] Re: Lunar trouble, need help
    
    
    
    Since my last Navlist posting, I've had a short spell in hospital, and my
    pocket calculator came with me. Now I'm back out again, I can report back on
    some findings, to show my time there wasn't entirely wasted.
    
    Jeremy wrote, in 5413-
    
    "Here is my data around 0620 on 10 June 2008.
    
    1) Sun LL: Hs 33deg 58.5� @ 06h 19m 13s UTC
    2) Moon UL:  60deg 36.8� @ 06h 20m 44s
    3) LD1: 86deg 10.3� @ 06h 21m 40s
    4) LD2: 86deg 10.0� @06h 22m 20s
    5) LD3: 86deg 10.2� @06h 22m 52s
    6) LD4: 86deg 10.6� @06h 23m 24s
    7) LD5: 86deg 10.6� @06h 24m 39s
    8) Sun LL: 32deg 35.8� @ 06h 25m 19s
    9) Moon UL: 61deg 49.2� @ 06h 26m 28s
    
    DR (didn�t take a fix) Latitude was 15deg 14.0�N and Longitude was
    144-04�E.  Ship was on course 270 at 12.0 knots.  IE was 0.0 T/P was
    98deg F and 1010MB.  Height of eye is 106 feet.
    
    I averaged the two sun lines to get 33deg 17.2� at 06h 22m 15s, then
    the two moon altitudes to get 61deg 13.0� at 06h 23m 37s.  Finally the
    5 LD�s averaged to 86deg 10.34� at 06h 22m 59s."
    
    =======================
    Those numbers didn't "add up", and Frank surmised (correctly, in my view)
    that overlapping, rather than the usual side-by-side, views of the Moon and
    Sun limbs had been taken.
    
    I've had a go at working that lunar in my own way; which means that I like
    to get out of those damned sexagesimals and into decimals, so I can use my
    calculator properly. I will spell it all out in more detail than if I were
    just calculating for myself.
    
    I agree with Jeremy and with Kent that the mean lunar distance is 86.1717�
    at a mean time of 6.3831hrs (give or take 2 or 3 arc-seconds, which between
    friends are not worth arguing about).
    
    That needs correcting for the two semidiameters, in this (odd) case by
    adding the Moon's semidiameter, of 0.2606� (which includes "augmentation" of
    0.0035�), and (unusually) subtracting the Sun's, of 0.2625�.
    
    so observed lunar distance between centres = 86.1698�   (this is d)
    
    Then we have to take a weighted-mean of the two Sun observations so that
    it's the same as if it had been taken at that same moment, which gives-
    Sun LL altitude at 6.3831 h = 33.1231�, which agrees pretty well with Kent's
    figure.
    Similarly,
    Moon UL altitude at 6.3831 h = 61.0879�, which disagrees a bit with Kent.
    
    Now for some corrections for the Moon
    61.0879 UL observed sextant alt Moon
     -.1667 dip
    --------
    60.9212 alt. above true horizon
     -.0083 refraction
    -------
    60.9129
     -.2606 less semidiameter Moon from UL obs.
    -------
    60.6523 alt Moon centre
     +.4622 parallax (=HP cos alt), where Moon HP = .9433�
    -.0002 reduction of parallax
    -------
    61.1143 =M, corrected altitude of Moon centre
    60.6606 =m, altitude of Moon centre before correction for parallax and
    refraction.
    ========================
    Similarly for the Sun
    33.1231 LL observed sextant alt Sun
     -.1667 dip
    -------
    32.9564 alt above true horizon
     -.0083 refraction
    --------
    32.9314
     +.2625 add semidiameter Sun to LL obs.
    --------
    33.1939
     +.0020 sun parallax based on Sun HP = .0024�
    --------
    33.1959 = S, corrected altitude of Sun centre.
    33.2189 = s, altitude of Sun centre before correction for parallax and
    refraction.
    
    Next we have to "clear" the observed lunar distance d of the effects of
    parallax and refraction, to arrive at the true lunar distance D.
    
    s and m are the altitudes of Sun and Moon corrected for everything except
    parallax and refraction.
    S and M are the altitudes of Sun and Moon corrected for everything including
    parallax and refraction.
    
    I use the formula-
    D = arc cos[(cos d - sin s sin m) cos S cos M /(cos s cos m) +Sin S sin M]
    and I get D= 85.7384�. This is the corrected lunar distance, that has to be
    compared with prediction.
    
    I've taken the predictions quoted by Kent (who may have "rolled his own",
    and they agree, within an arc-second with those you can get from Steven
    Wepster's website, at http://www.math.uu.nl/people/wepster/tables.html) and
    converted to decimal degrees, these are, for 10 June 08-
    
    GMT 0600, D = 85.5331�
    GMT 0900, D = 87.0181�
    and to deduce the time of the observation, we have to do a
    reverse-interpolation between them.
    
    The result I get is 06h 24m 53s as the final result for the GMT of the
    observation.
    
    This has to be compared with Jeremy's averaged chronometer time of 06h 22m
    59s for his lunar distances. So my conclusion is that his chronometer was
    slow by 1 minute 54 seconds. Or, perhaps more realistically, that his
    chronometer was correct and his lunar-derived GMT was in error by 1 minute
    54 seconds. That isn't a bad result, for a lunar. It would have put his
    deduced longitudes out by about 28.5 arc-minutes, which would have (but only
    just) qualified Jeremy for the Longitude Prize, if he had been observing
    around 240 years ago. The total error in angle in the whole process was less
    than an arc-minute, which for a first-shot at a lunar, is creditable work
    indeed.
    
    If anyone is bothered to check my numbers, and finds anything to question,
    or any step hard to follow, I hope he will let me know.
    
    That compares pretty well with what Kent Nordstrom deduced, in [5476], when
    he wrote-
    
    "By using my average time for the LD observations 06-22-59 the corresponding
    true LD from a NA is 85d 23m 43s. If I ,without paying attention to the GMT
    06-22-59 but only use this distance in my calculations I get a GMT of
    06-23-43."  I disagree (but only marginally), with that GMT, but it comes
    even closer to the time of Jeremy's observation than does my calculation;
    within a minute, indeed.
    
    However, I do NOT understand Kent when he continues-
    
    "At this time the sun�s apparent time is 16-59-47.5. The TE is +31.5 s,
    which gives the MT of 15-59-47.5 + 00-00-31,5=16-00-19.
    
    
    The difference between MT and GMT, that is 16-00-19 � 06-23-43=09-36-36 or
    corresponding to the long. E 144d 09m.
    
    
    
    So it seems to me that Jeremy�s distances are not correct."
    
    
    
    I don't see what Sun's apparent time has to do with the matter, or MT, or
    longitude. The aim of a lunar is to establish GMT, to set a local clock
    right; nothing more than that. Steven's web page of lunar predictions is
    marked as being for UT (= GMT), unlike the early almanacs, which until 1834
    were based on Greenwich Apparent Time. Kent's predictions must also be for
    GMT, so I suggest he is bringing in complications that don't exist.
    
    
    
    Armed, now, with a figure for GMT (if we ignore what the chronometer was
    saying), it's easy to deduce, from the Almanac, a position for the Sun (or
    the Moon, for that matter, or both) and from the observed altitude, generate
    position lines in the familiar way, which should provide a good longitude,
    but (from the way they cut) not a good latitude, which deserves another
    observation at a different time.
    
    
    
    ==========================================
    
    
    
    Jeremy wrote, in [5469]-
    
    
    
    "I will also say that getting lunars at sea will be inherently more
    inaccurate then land.  Roll alone can change my height of eye several feet
    and ship's vibration also make it more difficult to get a steady platform
    (it pretty much forces you to shoot while standing.)  I am actually quite
    happy with about 1' of error for sea lunars.  Sitting on a beach, I'd expect
    a bit better however...."
    
    Changing height of eye will have little affect on a lunar, being no more
    than a correction to a correction.
    
     Adding "... I don't have logs, but I was wondering how accurate old time
    sailors got with their lunars at sea?"
    
    I doubt if that's an easy question to answer. Trouble is, only recently have
    navigators known REALLY where they were when out in the ocean. Lunar
    distance navigation loses its point once land is in sight. So it's only when
    taking lunars for training and for practice that they would be taken from
    well-known positions, and then the results would seldom be logged.
    Comparisons of lunars with chronometers could be informative, if at the end
    of a voyage a chronometer had been shown to have kept good time overall, but
    I don't know of any retrospective study that has ever been made.
    
    Mariners usually had log trig tables available with sufficient decimal
    places (5 or 6) so as not to contribute significant error, together with
    familiarity in using them (though without much understanding of what they
    were doing, in general, I suspect).
    
    George.
    
    contact George Huxtable at george@huxtable.u-net.com
    or at +44 1865 820222 (from UK, 01865 820222)
    or at 1 Sandy Lane, Southmoor, Abingdon, Oxon OX13 5HX, UK.
    
    
    
    
    
    
    
    
    
    
    
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