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    Re: Lunar Distances with Alex's SNO-T
    From: Alexandre Eremenko
    Date: 2006 Oct 31, 15:41 -0500

    Jean-Philippe says that the airport is 606.
    Fred says that my appartment is 670.
    Well, the road from the airport to my place goes up
    indeed. By 54ft? A bit surprising.
    And you say that your appartment is 707.
    (Your appartment is 37 ft higher?
    Could be, of course...)
    What is your result for my appartment?
    On Tue, 31 Oct 2006, Bill wrote:
    > Alex
    > I have a topo map for our area.  My apartment is just about 705 feet above
    > sea level.  Yours should be close, perhaps a bit lower.  The Wabash river in
    > is approx. 520 ft in Lafayette/West Lafayette.  Will look up your place if
    > you wish.
    > According to USA Today:
    > http://www.usatoday.com/weather/resources/askjack/wfaqpres.htm
    > "The pressure reported for Denver, or any official observation station for
    > that matter, is not the actual pressure on the surface, but rather is the
    > pressure corrected to sea level. The reason this is done is so that
    > meaningful maps of constant pressure lines, called isobars, can be drawn for
    > stations across the USA. These maps are useful for picking out areas of
    > relative high and low pressure. If pressure readings were not corrected,
    > places like Denver would almost always have lower pressure than spots at
    > lower elevations. Essentially, the map would reflect topography, rather than
    > weather systems in the atmosphere."
    > A while back Frank, if I recall, gave a method for converting the broadcast
    > barometric pressure to local station pressure.
    > On a calculator divide your altitude above see level by -32000 (maybe
    > -34000?).  Then hit (on my TI-30XA) 2nd then LN.  (You are looking for e^x,
    > the mathematically inclined can say it better, but that's the cookbook
    > method).
    > Multiply the broadcast pressure by the above result to get local (station)
    > pressure.  I use it with inches Hg, so not sure if it also works in
    > millibars, but don't see why it would not.  Perhaps Frank can clear up my
    > fuzzy memory.
    > There is some interesting information a well as a formula at:
    > http://en.wikipedia.org/wiki/Atmospheric_pressure
    > Bill
    > >
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