# NavList:

## A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding

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From: David C
Date: 2020 Apr 29, 16:40 -0700

Tibor wrote

May I contribute with a Dreisonstok solution for completness? :-)

I am forced to calculate the azimuth with Table V in HO200 (-;

This method uses altitude, dec and hour angle, unlike most other tables wich use lat, dec and hour angle.

h  33° 03.7'

dec  14°  13'

t  15°

With dec and t extract 9.39990

With h in the dec column look for the number closest to 9.9990 .  Azimuth is  the corresponding hour angle  =  17°.  With some very rough interpolation azimuth = 17.5.°.   dec and lat are of contrary names so azimuthis named opposite of lat -----  N 17.5° E. This is the bearing method of naming azimuth.   If the names are the same the rule is complicated and I have not attempted to decypher it.

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