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    Leg 60
    From: R. Winchurch
    Date: 2000 Mar 23, 09:25 EST

    # 2. Distance 88.5 nm
    # 3.  190d t
    But I cheated and I am somewhat confused by my answers.  I used a
    program entered into my TI 60 calculator for determining Hc and Z.  I
    computed lha by the difference between my lat and the long. of the
    waypoint.  I entered my lat and substituting  the lat for the waypoint
    for dec in the program.
    Then I checked my calculations using the Nav20 program in the archive.
    My question is this.  The program calculates Hc which is in degrees
    between the assumed position and the gp of the body (in this case it
    would be the waypoint. Since 1 degree equals 60 nm the calculated
    distance should have been 60 X the degrees arrived at from the
    calculation or 5310 nm.  How  did Nav 20 come up with 88.5 nm?

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