NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Leg 60
From: R. Winchurch
Date: 2000 Mar 23, 09:25 EST
From: R. Winchurch
Date: 2000 Mar 23, 09:25 EST
# 2. Distance 88.5 nm # 3. 190d t But I cheated and I am somewhat confused by my answers. I used a program entered into my TI 60 calculator for determining Hc and Z. I computed lha by the difference between my lat and the long. of the waypoint. I entered my lat and substituting the lat for the waypoint for dec in the program. Then I checked my calculations using the Nav20 program in the archive. My question is this. The program calculates Hc which is in degrees between the assumed position and the gp of the body (in this case it would be the waypoint. Since 1 degree equals 60 nm the calculated distance should have been 60 X the degrees arrived at from the calculation or 5310 nm. How did Nav 20 come up with 88.5 nm?