NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: LAN sight correction..
From: Russell Sher
Date: 1999 Aug 13, 7:49 AM
From: Russell Sher
Date: 1999 Aug 13, 7:49 AM
I think that the Zone in my example should have been 8 (not 9) since that would give 12 36 for ZT LAN which would be later as expected than if the observer was at 120 W long. See below... example - say that you were at Longitude 127 degrees 30 minutes West and mer pass is given as 1206. You would solve as follows: 1) convert the 127 deg. 30 minutes to time - (Hint: an easy way is to divide by 15) This gives 8hours 30minutes in time. 2) As you correctly stated you would ADD (because it is West long) the 8 hours 30 min in time to 1206. This gives you- 20 36 UTC. For LAN at you longitude. 3) If you want to express this UTC time of LAN in your local time, then you need to subtract your Zone offset (i.e. the difference in whole hours between your local time and UTC) - Say in this case that it is 8 hours behind UTC, then you would take 20 36 - 08 00 = 12 36 ZT. for LAN. 4) Note that if you were situated exactly on the central meridian of your time zone e.g. at say 120 degrees W. Then the ZT of LAN would equal the LMT of mer pass i.e. 1206. In this case. This is because you would take 1206 + 0800 - 0800 which would give 12 06. In such a case, your watch if set to local time would agree with the time given for mar pass on the daily page. The confusing bit is that although we all keep the same local time within a zone, two observers placed at each end of the same zone (i.e. 15 degrees apart) would experience LAN one hour apart in time although their watches would read the same ZT. Hope that helps Ask further if you like... Russell