A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
From: Gary LaPook
Date: 2011 Mar 19, 18:15 -0700
|When a reactor is shut sown it continues to release energy due to decay of radioactive products which amounts to 6.5% of the prior power output at the time of shut down. From this 6.5% the decay heat drops off rapidly given by the formula |
P now = P at shutdown X .066 (time in seconds since shutdown) ^ -.2
The reactors were shut down at approximatly 0500 Z March 11 and it is approximately 0000Z March 20th now. Eight days and nineteen hours have elapsed, 759,600 seconds so the decay heat now should be only 0.44%. The reactors power output are 784 mw so the decay heat now is 3.48 mw. It takes 628 watt-hours to boil a liter of water so the reactor will be able to boil 5542 liters per hour, 92 liters per minute and this is the amount of water that must me fed into the reactor core now to keep it from melting further.
--- On Sat, 3/19/11, Alan <firstname.lastname@example.org> wrote: