NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Interpolation of Meridional Part Table
From: NavList
Date: 2009 Mar 24, 12:42 -0700
From: NavList
Date: 2009 Mar 24, 12:42 -0700
Anyone, I am looking at a sample problem in section 505 of the 1972 Dutton's. It says that the latitude of Cape Flattery Light is 48d23.5' and says that the meridional parts (m) for that latitude are (is?) 3309.2. Using an on-line versuion of Bowditch Table 6, I located 48 deg latitude and went down the minutes column to 23' to find m=3308.8, and to 24' to find m=3310.3. A linear interpolation would put 48d23.5' at 1/2 the difference, or 3309.55 (round up or down to taste), and one would then have m=3309.5 or 3309.6. I recognize that a linear interpolation doesn't really fit the facts as far as the way meridional parts change; so is there a technique I shold know about that would have given me the result Dutton's got, 3309.2? That is, how did they do that? -John Parsons --------------------------------------- [Sent from archive by: jkp-AT-obec.com] --~--~---------~--~----~------------~-------~--~----~ Navigation List archive: www.fer3.com/arc To post, email NavList@fer3.com To , email NavList-@fer3.com -~----------~----~----~----~------~----~------~--~---
