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    Re: Hav-Doniol re-visited
    From: Greg Rudzinski
    Date: 2020 Oct 22, 17:20 -0700

    1955 Doniol                                                  Haversine Doniol

    sin(hc)=n-(n+m)a                                         hav(ZD)=n+[1-(n+m)](a)

    n=cos(L-d) same name                                n=hav(L-d) same name

    n=cos(L+d) contrary name                           n=hav(L+d)contrary name

    m=cos(L+d) same name                              m=hav(L+d)same name

    m=cos(L-d) contrary name                           m=hav(L-d)contrary name

    a=hav(t)                                                        a=hav(t)

    Greg Rudzinski

       
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