A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Position-Finding
From: Tony Oz
Date: 2018 Aug 6, 02:56 -0700
On 2018 Jan 23, 06:42 -0800 you wrote:
Starting at a latitude, longitude L0, λ0 and traveling a distance D(°) on a course C° measured East from North the necessary formulas are:
sin L = sin L0 cos D + cos L0 sin D cos C
sin ( λ - λ0 ) = sin D sin C / cos L
Thank you for the formula.
While making it into my TI-83+ I discovered that as given it works only within the nearest 5400 nm.
To make it work around the globe I had to amend it like that:
λ = λ0 + arcsin(sin(D)sin(C)/cos(L))
if D > 90° then; λ = 180° - (λ0 + arcsin(sin(D)sin(C)/cos(L)))
Now, as far as I can test, - it works for any distance, even for 21600 nm.