A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
From: Ron Jones
Date: 2019 Feb 19, 10:57 -0800
On 2019 Feb 18, 13:25 -0800 Paul Hirose wrote:
How do you get (ZnMoon – ZnBody)? It's dependent on time and location, so a calculated value won't do.
The equation only depends on the difference in azimuth, therefore a pelorus could be used to find (ZnMoon – ZnBody) to within ±0.5°