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RE :
http://www.fer3.com/arc/m2.aspx?i=115660
[NavList] Re: Friendly challenge : Jupiter Lunar Exercise 09 Feb 2011
From: cfuhb-acdgw---net
Date: 13 Feb 2011 13:28

Dear Paul,

Thank you very much for your very interesting solution. I printed it, as I earlier did for the one sent by Frank, and I am keeping it in my archives folder altogether with the solution I derived through the use of Frank's On-Line Computer.

******* ******* ******* ******* ******* ******* *******

Interesting to see our various results :

Further to my initial post ( http://www.fer3.com/arc/m2.aspx?i=115625 ) , I published in ( http://www.fer3.com/arc/m2.aspx?i=115633 ) my Actual position which was :

Steady Observer N4642.9W00223.7

*******

Frank's results (http://www.fer3.com/arc/m2.aspx?i=115630) show :

Lunar Distance UT = 18h07m30s , N4642.4W00226.0

*******

With Frank's On Line Lunar Computer (http://www.fer3.com/arc/m2.aspx?i=115633) I derived the following position :

Lunar Distance UT = 18h07m27.0s , N4643.1W00226.2

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You just published (http://www.fer3.com/arc/m2.aspx?i=115660) your own results as :

Lunar Distance UT = 18h07m38s , N4643.04W00229.1

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I had earlier found (bottom lines of document "115633.one-solution-to-the-jupiter-.pdf" published as Attached File in http://www.fer3.com/arc/m2.aspx?i=115633)

Lunar Distance UT = 18h07m33.8s , N4643.2W00228.1

Last note : For this solution, I performed my own computations with TT-UT=67.2s

*******

Thank you again for your Kind Attention and Warmest Congratulations for your very interesting reply and solution.

Best Friendly Regards

Kermit

Antoine M. "Kermit" Couëtte

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