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    Re: Finding The Symmedian
    From: Peter Fogg
    Date: 2010 Dec 28, 14:07 +1100
    Herbert Prinz wrote:
    On 2010-12-24 13:56, Peter Fogg wrote:
    OK, I think I can answer my own question; the distances b and c are the lengths of the sides b and c of the triangle, which leads to another question:

    Correct.

    Does the line connecting A' and A bisect the angle A?

    if and only if b = c.

    Proof: AA' bisects angle A <-> x = y < -> x : y = 1 <-> b : c = 1 <-> b = c

    Herbert Prinz then amended the above with:

    A spurious blank in my previous message makes it difficult to read. It should have said:

    Proof: AA' bisects angle A <-> x = y <-> x : y = 1 <-> b : c = 1 <-> b = c

    ............................................................................................................................


    I did find that extra blank, although it didn't make a lot of difference as to how easy it was to read.  I take it the notation reads: A is greater or lesser or the same as x which equals y, which is greater or lesser or the same as x : (what does the colon signify?)

    Thanks for this, Herbert.  Can you, or ayone else with an idea, explain why this Symmedian point should be preferred as defining the centre of a triangle over any other centre of a triangle?

    In particular, what advantage does the Symmedian offer in comparison to a triangle centre which this site calls the Incenter:

    http://www.jimloy.com/geometry/centers.htm


       
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