# NavList:

## A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding

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Re: Finding The Symmedian
From: Gary LaPook
Date: 2010 Dec 17, 13:36 -0800
 Now that we know that the Symmedian point is the actual highest probability point, it now appears that the point that we had discarded early in this discussion because it was far away from the medians, the Steiner point, is the best approximation of the Symmedian point and is a whole lot easier to draw. See my diagrams at: http://www.fer3.com/arc/m2.aspx?i=114723&y=201012gl--- On Fri, 12/17/10, Gary LaPook wrote:From: Gary LaPook Subject: [NavList] Re: Finding The SymmedianTo: NavList@fer3.comDate: Friday, December 17, 2010, 1:23 PMGreg, I don't think your method actually produces the Symmedian point. It is my understanding that you measure the angle (at the vertex) between the median and the bisector (not the spacing) and then draw the line the same number of degrees on the side opposite to the median, basically flipping the median over using the bisector as the axis. Your method only approximates this for some triangles but try in on the 20-70-90 triangle that I posted before:http://www.fer3.com/arc/m2.aspx?i=114765&y=201012gl----------------------------------------------------------------NavList message boards and member settings: www.fer3.com/NavListMembers may optionally receive posts by email.To cancel email delivery, send a message to NoMail[at]fer3.com----------------------------------------------------------------
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