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    Re: Figuring Course given Lat/Long of destination
    From: Ed Kitchin
    Date: 2000 Feb 28, 7:09 AM

    Thank you, Tony. In other words, I could construct a solution on the univ.
    plotting sheet, as I mentioned, but use the mean of departure, and
    destination latitudes, and that would work? Thank you.
    ----- Original Message -----
    From  "Tony" 
    Sent: Sunday, February 27, 2000 9:00 PM
    Subject: Re: Figuring Course given Lat/Long of destination
    > Ed:
    > When you say that "there is the error of the Macerator thing", can you be
    > more specific?  Did you use Bowditch Mercator sailing by tables?  This
    > should work out OK.
    > Actually, just using Plane sailing with mid-latitude should be quite close
    > because the distance is relatively short; only earth eccentricity is
    > Why the problem suggests also GC (great circle) does not make much sense.
    > There would be less than a mile difference.  I did check the results by
    > computer and they are OK.  [ Sometimes they are not. ;) ]
    > Tony    in San Francisco
    > > Ed Kitchin wrote:
    > >
    > > An interesting problem appears in the latest issue of "Ocean Navigator"
    Which asks that you figure
    > > the course to a destination given origination and destination. It would
    seem easy to determine the
    > > difference in lat. (The destination was over several degrees of lat.),
    but deg. of long. differ in
    > > length as you change lat. One could simply take the mean of the two
    given long. and use that, but
    > > that bothers me as not being all that accurate. There is the error of
    the Macerator thing. You
    > > could use universal plotting sheets and construct using a vertical
    representing diff./lat., then
    > > draw a horizontal from the top of the lat. fig., representing the long.
    at the destination, and
    > > draw a hypotenuse as the course line. (???) Are there any mathematicians
    out there to
    > >  give me a good formula to learn for this task? Thank you.
    > >
    > > Ed Kitchin

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