NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
From: Andrés Ruiz
Date: 2008 Jun 13, 10:49 +0200
gyro error =
231.9-232.7 = -0.8º
Fecha y hora UT1
12/06/2008
19:29:00
SITUACION ESTIMADA
Latitud: Be = 15.233333 º = 15º 14.0'
Longitud: Le = 145.116667 º = 145º 7.0'
ALMANAQUE NAUTICO
Cuerpo celeste: Planeta Jupiter
Polo de iluminacion del astro: Coordenadas
Ecuatoriales
GHA = 261.445097 º = 261º 26.7'
Dec = -21.988427 º = -21º 59.3'
Correcciones altura:
SD = 0.384586 '
HP = 0.034311 '
DETERMINANTE DE
Angulo Horario Local: LHA = 46.561764 º = 46º 33.7'
Coordenadas Horizontales: Hc, Z
Altura Calculada: Hc = 31.1163 º = 31º 7.0'
Azimut: Z = 231.9 º
Andrés
-----Mensaje original-----
De:
Enviado el: viernes, 13 de junio de 2008 10:35
Para: NavList
Asunto: [NavList 5414] Exercise #13 Azimuth of a planet
Exercise #13 Azimuth of a planet
On 13 June
check off list, there is a box stating
“gyro error calculated and
posted.” The sky is mostly
overcast and the sun looks like it will be
obscured by clouds for most of the
morning. Fortunately abaft of the
starboard beam, Jupiter is shining
brightly in the late morning
twilight. The alidade was set up on the
starboard gyro compass
repeater and a bearing was taken at 05h
29m 00s ZT. (ZD -10). The
bearing was 232.7 degrees. The ship is
in position Latitude 15deg
North, Longitude 145deg 07’East.
Determine the gyro error for
arrival.
Jeremy
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