# NavList:

## A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding

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Re: Doing my homework
From: Tony Oz
Date: 2016 Nov 4, 07:06 -0700

Dear John,

LHA + EsLon 3° + (-66°30') = 3° - 66°30' = -63°30'.

LHA is always between 0° and 360° so you must "normalize" the negative LHA by adding 360° to it. ( If LHA was 425° you would subtract 360° )

LHA = -63°30' + 360° = 296°30'

LHA is Greater than 180° so the second rule would be used ie t = 360° - LHA

t = 360° - 296°30' = 63°30'

Thank you for further clarification. It confirmed that I did get your explanations correctly. I'll contact the author of that SR work-sheet to amend the instructions for the Step 1 accordingly.

Warm regards,

Tony

PS

Could Step 1 be simplified by not dealing with LHA at all? Could I get t directly from GHA and LonEP observing the "+ is East, - is West" rule? I think it would be less error-prone.

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