
NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Dip-meter again
From: Marcel Tschudin
Date: 2013 Apr 13, 11:46 +0300
From: Marcel Tschudin
Date: 2013 Apr 13, 11:46 +0300
Bruce, A precise horizontal distance alone is not sufficient for observing the dip variations. You also need a "fixed" horizontal reference line, e.g. a fence, a border or a roof within a short distance e.g. 100m to 300m where refraction is likely still negligible. For my observations I did not have a horizontal reference line. In a few cases I could however observe a remarkable change in refraction between horizon and a feature protruding from behind it. The attached picture shows two such situations where the apparent horizon differs by about 5 moa compared to the island behind it. Victor Reijs shows on his Web-page here http://www.iol.ie/~geniet/eng/refract.htm#limiting a plot with published refraction measurements near the horizon. One series of measurements (Seidelmann) show a systematic difference between sunrise and sunset of about 6 moa. This difference may be specific to the location where the measurements were made. Marcel On Sat, Apr 13, 2013 at 6:25 AM, Bruce J. Penninowrote: > ________________________________ > > Hi Frank and All: > > Frank, you've mentioned this thought (vanishing buildings) before. I hate > to admit it, measuring refraction in this manner is intriguing. Maybe my > next thought fits. Now that we know that we can get precise horizontal > distances between objects (I'm now thinking tall slender building or towers > in a row.....oil rigs or wind turbines). We also know that with my common > theodolite I can measure vertical angles to 3 seconds or so of vertical arc. > I really don't believe +/- 3 seconds because I still don't have operator and > collimation errors totally sorted out. Say I really can confidently measure > to +/- 10 seconds. > > I could set up someplace where I can see these two or three > buildings/towers several miles apart. How much does the meteorological > conditions have to change for me to measure the CHANGE in refraction based > on the apparent change in vertical heights of the building? Does the > temperature have to change 30F; weather front come through going from > relatively low atmospheric pressure to high pressure; where does relative > humidity come in? How about the azimuth of viewing; time of the year, angle > of the sun , and I'm sure many things I have not considered? Doable? > > Or, how about setting up a camera with a special lens or a stadia type > attachment and monitoring the buildings . Monitor weather at the same time. > By stadia eyepiece I mean several horizontal index lines or equivalent. > Knowing the height of the camera and buildings, and changes in apparent > height of the buildings, I believe you wrote that we could calculate > refraction change. Just thinking and trying to relate your thoughts and > those presented by Marcel. Seems difficult to quantify? > > Probably should rename this topic? > > Bruce > > > > > > > > > > > > > > > > > ----- Original Message ----- > From: Frank Reed > To: bpennino.ce---net > Sent: Friday, April 12, 2013 1:53 PM > Subject: [NavList] Re: Dip-meter again > > ________________________________ > > Gary, you wrote: > " I realized that I could get an accurate measurement of the width of the > channel by using Google Earth and that I could measure the angle below the > horizon to the waterline on the opposite breakwater and with this > information calculate my accurate height of eye." > > If I've understood your description correctly, essentially you're using "dip > short" to get height of eye. And yes, this works exceptionally well in cases > like this where you can figure out the exact linear distance to some feature > with a clearly defined waterline. > > Next, suppose you have several objects with clearly defined waterlines at > exactly known distances between you and the horizon (ideally, these would be > at regular intervals, e.g. a mile apart). If you measure the angles from > their waterlines to the horizon, it should be possible to solve for height > of eye AND the terrestrial refraction constant k (the rotation of a light > ray in minutes of arc per nautical mile). And if you return to the same site > under different weather conditions, you should find that the angles change > as k changes. Visually, the more distant objects would appear to group > together or spread apart vertically as the refraction changes. I'm still > hoping someone will make a great time-lapse video of this showing the > refracted view of objects towards the horizon breathing in and out during > the course of a day. > > -FER > > ---------------------------------------------------------------- > NavList message boards and member settings: www.fer3.com/NavList > Members may optionally receive posts by email. > To cancel email delivery, send a message to NoMail[at]fer3.com > ---------------------------------------------------------------- > > View and reply to this message: http://fer3.com/arc/m2.aspx?i=123545 > > View and reply to this message: http://fer3.com/arc/m2.aspx?i=123548